Hi,

The “print test_struct.var” command does print the correct output of the test_struct.var member and not the local var variable:

&"print test_struct.var\n"
$1 = 22

The GUI does still however show the local var variable value when you hover over the ‘.var’ member. When you hoover over the test_struct variable though it shows the correct value of the var member and also the ‘Autos’ and ‘Locals’ windows shows it correct. It’s just that when you hoover over the “var” part of the “test_struct.var” code that it shows wrong. It also as you can see shows the variable name as “var” only and not “test_struct.var” which it usually does when it shows the correct struct member value.

Optimization is set to “Disabled (-O0)”. I haven’t done any changes from the default project template for a linux application and run the Debug configuration of that.

Hi,

The “Watch” window shows the correct value as well. I think the issue is that when you hoover over the “var” part of “test_struct.var” it doesn’t recognize it as a member of the test_struct struct but just shows the local variable “var” instead.

I changed the code a bit to show more clearly what I mean. When I hoover over the “no_var” part of “test_struct.no_var” member the popup window shows “test_struct.no_var | 0x0000016”. But when I hoover over the “var” part of “test_struct.var” it just shows “var | 0x0000000a”. No “test_struct.” before “var”.

New code:

#include <iostream>

using namespace std;

typedef struct {
  int var;
  int no_var;
} TestStruct;

TestStruct foo( int var )
{
  TestStruct test_struct;
  test_struct.var = 22;
  test_struct.no_var = 22;

  test_struct.var = var;
  test_struct.no_var = var;

  return test_struct;
}

int main( int argc, char * argv[] )
{
  TestStruct test_struct = foo( 10 );
  return 0;
}

Hi,

That did indeed solve it.

Thanks!